2(s+2)^2-9(s+2)=5

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Solution for 2(s+2)^2-9(s+2)=5 equation: 



2(s+2)^2-9(s+2)=5

We move all terms to the left:

2(s+2)^2-9(s+2)-(5)=0

We multiply parentheses

2(s+2)^2-9s-18-5=0

We add all the numbers together, and all the variables

-9s+2(s+2)^2-23=0

We move all terms containing s to the left, all other terms to the right

-9s+2(s+2)^2=23

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